计算int dfrac (1)({(1-{x)^2)}^dfrac (3{2)}}dx；

[题目]-|||-int (dfrac (3)(1+{x)^2}-dfrac (2)(sqrt {1-{x)^2}})dx

(6) () =dfrac (1)(sqrt {1-{x)^2}} int dfrac (1)(sqrt {1-{x)^2}}dx=() .

计算积分(int )_(dfrac {1)(2)}^dfrac (3{2)}dfrac (dx)(sqrt {|x-{x)^2|}}.(本题满分6分)计算积分.

计算下列定积分.-|||-(int )_(dfrac {sqrt {2)}(2)}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx -

int dfrac ({x)^3}({(1+{x)^2)}^2}dx=A.int dfrac ({x)^3}({(1+{x)^2)}^2}dx=B.int df

(15) int dfrac ({x)^2}(sqrt {1-{x)^2}}dx

(3) int dfrac (1)({(1+{x)^2)}^dfrac (3{2)}}dx;

int dfrac (dx)(x+sqrt {1-{x)^2}}..

[题目] int dfrac (x)(sqrt {1-{x)^2}}dx

int dfrac (dx)(x+sqrt {1-{x)^2}}