5.已知 (x)=sum _(n=1)^infty ((-1))^n-1dfrac (1)((2n-1)!)((pi x))^2n-1 则 f(1)=()-|||-

幂级数sum _(n=1)^infty dfrac ({(-1))^n}(2n-1)(x)^2n-1(|x|lt 1)的和函数sum _(n=1)^infty

,求幂级数 sum _(n=1)^infty dfrac (2n-1)({2)^n}(x)^2n-2 的和函数,并求级数 sum _(n=1)^infty df

1.求下列幂级数的收敛域(或收敛圆):-|||-(1) sum _(n=1)^infty dfrac (1)({2)^n}(x)^2n-1;-|||-(2) s

+dfrac (1)({(2n-1))^2}(2n-1)x+... ] -|||-(B) dfrac (2)(pi )[ dfrac (1)({2)^2}sin

如果级数 sum _(n=1)^infty dfrac ({(2x-a))^n}(2n-1) 的收敛区间是(3,4)则 a=-|||-

(1995,数一)幂级数 sum _(n=1)^infty dfrac (n)({2)^n+((-3))^n}(x)^2n-1 的收敛半径 R= __

+dfrac (1)(n(n+1)) =-|||-(3) lim _(narrow infty )(dfrac (1)(2)+dfrac (3)({2)^2}+

+dfrac (1)((2n-1)(2n+1))]求极限

1.求下列幂级数的收敛半径、收敛区间、收敛域.-|||-(1) sum _(n=1)^infty ((-1))^n-1dfrac ({x)^n}({n)^2}

5.下列级数中,条件收敛的是 () .-|||-(A) sum _(n=1)^infty ((-1))^n-1dfrac (n)(sqrt {{n)^3+1}}