( (int )_(dfrac {pi )(4)}^dfrac (pi {3)}dfrac (x)({sin )^2x}dx ;
已知函数 (x)=dfrac (1)(2)sin (2x-dfrac (pi )(3)) x∈R,-|||-(1)求f(x)的最小正周期;-|||-(2)求f(
计算 lim _(xarrow dfrac {pi )(2)}dfrac (ln sin x)({(pi -2x))^2}
求lim _(xarrow dfrac {pi )(2)}dfrac (ln sin x)({(pi -2x))^2}求
(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}dfrac (|x|sin x)(1+{cos )^3x}dx=(int )_(-
dfrac (2pi )(sqrt {3)} D. dfrac (pi )(6)
dfrac (2pi )(sqrt {3)}-|||-D. dfrac (pi )(6)
πm·s^(-1))=dfrac (dy)(dt)=Rtdfrac (2pi )(T)cos dfrac (2pi )(T)ti+ndfrac (2pi )(T
3.要使函数φ(x )= ,dfrac {pi )(2)] (B)[π,2π] (C) [ 0,dfrac (pi )(2)] (D) [ dfrac
[题目]求函数 =2sin 3x, .in [ -dfrac (pi )(6),dfrac (pi )(6)] 的反函-|||-数.