[题目]设L为球面 ^2+(y)^2+(z)^2=(a)^22 被平面 x+y+z=0 所-|||-截的圆周,则 (int )_(1)((x)^2+(y)^2)
球面^2+(y)^2+(z)^2+4x+6y+2z+10=0的球心坐标为A.^2+(y)^2+(z)^2+4x+6y+2z+10=0B.^2+(y)^2+(z)
( A ) = (x,y,z)|{x)^2+(y)^2+(z)^2=(a)^2,zgeqslant 0} ( B ) = (x,y,z)|{x)^2+(y)^
设(x,y,z)=(x)^2+(y)^3+z,求(x,y,z)=(x)^2+(y)^3+z,在点(x,y,z)=(x)^2+(y)^3+z,处沿方向(x,y,z
[题目]求函数 =(x)^2+(y)^2+(z)^2 在约束条件 =(x)^2+(y)^2 和-|||-x+y+z=4 下的最大值与最小值.
【题目】-|||-求平行于平面 _(0):x+2y+3z+4=0 ,且与球面 sum :(x)^2+(y)^2+(z)^2=9-|||-相切的平面Ⅱ的方程.
椭球面^2+2(y)^2+(z)^2=1上平行于平面^2+2(y)^2+(z)^2=1的切平面方程( )^2+2(y)^2+(z)^2=1^2+2
设I为空间曲线 ) (x)^2+(y)^2+(z)^2=(R)^2 x+y+z=0-|||-B πR 2-|||-C 2πR 3-|||-D 2πR 2
设 ^2+(y)^2+(z)^2-4z=0, 求 dfrac ({a)^2z}(q{x)^2}
4.计算下列曲面积分:-|||-(3) int [ ((x+y))^2+(z)^2+2yz] dS, 其中∑是球面 ^2+(y)^2+(z)^2=2x+2z;