1.下列等式不成立的是 () .-|||-(A) =ABcup Aoverline (B); (B) -B=Aoverline (B);-|||-(C) (overrightarrow (AB))(overrightarrow (AB))=; (D) (A-B)cup B=A.

5.单远题-|||-下列等式不成立的是 ()-|||-(A) cup B=(Aoverline (B))cup B-|||-(B) -B=Aoverline (

证明下列事件的运算公式：(1) =ABcup Aoverline (B) __(1) =ABcup Aoverline (B) __证明下列事件的运算公式：

A，B，C是任意事件，在下列各式中，不成立的是（）(A) (A-B)cup B=Acup B.-|||-(B) (Acup B)-A=B.-|||-(C) (A

2.设A,B为二随机事件,则 (ABcup Aoverline (B))(Acup overline (A)overline (B))= ()-|||-(A)A

2.设A,B为二随机事件,则 (ABcup Aoverline (B))(Acup overline (A)overline (B))= ()-|||-(A)A

2.1.2 用逻辑代数定律证明下列等式:-|||-(1) +overline (A)B=A+B-|||-__-|||-(2) +Aoverline (B)C+A

10.证明下列事件的运算公式:()-|||-(1) =ABcup Aoverline (B); __-|||-(2) cup B=Acup overline (

10.证明下列事件的运算公式:-|||-(1) =ABcup Aoverline (B);-|||-__-|||-(2) cup B=Acup overline

1.设P(A)=0.4，P(B)=0.3，P(A∪B)=0.6，则P(Aoverline(B))=（）.A. 0.1B. 0.3C. 0.2D. 0.5

1.(1)已知P(overline(A))=0.3，P(B)=0.4，P(Aoverline(B))=0.5，求P(B|A∪B)；1.(1)已知$P(\over