A，B，C是任意事件，在下列各式中，不成立的是（）(A) (A-B)cup B=Acup B.-|||-(B) (Acup B)-A=B.-|||-(C) (Acup B)-AB=Aoverline (B)cup overline (A)B.-|||-(D) (Acup B)overline (C)=(A-C)cup (B-C).

A，B，C是任意事件，在下列各式中，不成立的是（）

参考答案与解析：

相关试题

设A、B、C是任意三个随机事件，则下列命题正确的是( )(Acup B)-B=A-B(Acup B)-B=A-B(Acup B)-B=A-B(Acup B)-B=A-B

设A、B、C是任意三个随机事件，则下列命题正确的是( )(Acup B)-B=A-B(Acup B)-B=A-B(Acup B)-B=A-B(Acup B

  • 查看答案

    • 二、化简下列各式-|||-1、 (Acup B)(overline (A)cup B)(Acup overline (B))

    二、化简下列各式-|||-1、 (Acup B)(overline (A)cup B)(Acup overline (B))

  • 查看答案

    • A，B为两事件，若(Acup B)=0.8，(Acup B)=0.8，则（）成立.A.(Acup B)=0.8B.(Acup B)=0.8C.(Acup B)=0.8D.(Acup B)=0.8

    A，B为两事件，若(Acup B)=0.8，(Acup B)=0.8，则（）成立.A.(Acup B)=0.8B.(Acup B)=0.8C.(Acup B)=

  • 查看答案

    • (1)(overline(AB)cup C)(overline(AC)); (2)(Acup B)(Acupoverline(B)).6.证明:(Acup B)-B=overline(AB)=A-A

    (1)(overline(AB)cup C)(overline(AC)); (2)(Acup B)(Acupoverline(B)).6.证明:(Acup B

  • 查看答案

    • 1.证明:-|||-(1) (Acup B)|C=A|(Bcup C) ;-|||-(2) (Acup B)|C=(A|C)cup (B|C) -

    1.证明:-|||-(1) (Acup B)|C=A|(Bcup C) ;-|||-(2) (Acup B)|C=(A|C)cup (B|C) -

  • 查看答案

    • (1)设事件A与B相容,则有 ()-|||-(A) (Acup B)=P(A)+P(B);-|||-(B) (Acup B)=P(A)+P(B)-P(AB);-|||-(C) (Acup B)=1-P

    (1)设事件A与B相容,则有 ()-|||-(A) (Acup B)=P(A)+P(B);-|||-(B) (Acup B)=P(A)+P(B)-P(AB);-

  • 查看答案

    • 5.单远题-|||-下列等式不成立的是 ()-|||-(A) cup B=(Aoverline (B))cup B-|||-(B) -B=Aoverline (B) .-|||-(C) =(AB)cu

    5.单远题-|||-下列等式不成立的是 ()-|||-(A) cup B=(Aoverline (B))cup B-|||-(B) -B=Aoverline (

  • 查看答案

    • [题目]证明 cup (Bcap C)=(Acup B)cap (Acup C)

    [题目]证明 cup (Bcap C)=(Acup B)cap (Acup C)

  • 查看答案

    • 2.对于任意的事件A、B、C，已知 P(A)=0.6, P(B)=0.4, P(C)=0.2, 求:(1) P(Aoverline(B))=0.3, 求 P(Acup B);(2) P(Acup B)

    2.对于任意的事件A、B、C，已知 P(A)=0.6, P(B)=0.4, P(C)=0.2, 求:(1) P(Aoverline(B))=0.3, 求 P(A

  • 查看答案

    • 2.设A,B为二随机事件,则 (ABcup Aoverline (B))(Acup overline (A)overline (B))= ()-|||-(A)A (B)B (C)AB (D)∅

    2.设A,B为二随机事件,则 (ABcup Aoverline (B))(Acup overline (A)overline (B))= ()-|||-(A)A

  • 查看答案