[题目]证明 cup (Bcap C)=(Acup B)cap (Acup C)
(1)(overline(AB)cup C)(overline(AC)); (2)(Acup B)(Acupoverline(B)).6.证明:(Acup B
设A,B,C相互独立, (A)=P(B)=P(C)=0.5, 则 (Acup Bcup C)=-|||-[填空1]
1.已知事件A,B,C,则以下结论错误的是 () .-|||-(a) overline (AB)=overline (A)cup overline (B) (b
5.化简:-|||-(1)(AB∪C)(AC);-|||-(2) (Acup B)(Acup overline (B)).
A,B,C是任意事件,在下列各式中,不成立的是()(A) (A-B)cup B=Acup B.-|||-(B) (Acup B)-A=B.-|||-(C) (A
(1)设事件A与B相容,则有 ()-|||-(A) (Acup B)=P(A)+P(B);-|||-(B) (Acup B)=P(A)+P(B)-P(AB);-
10.设事件A,B,C两两独立,其概率分别为0.2,0.4,0.6, (Acup Bcup C)=0.76, 则-|||-概率 (overline (A)cup
1.2.指出下列关系中那些是正确的,那些是错误的,并说明理由-|||-(1) (Acup B)-C=Acup (B-C);-|||-(2) (Acup B)-A
2.对于任意的事件A、B、C,已知 P(A)=0.6, P(B)=0.4, P(C)=0.2, 求:(1) P(Aoverline(B))=0.3, 求 P(A