[题目]证明 cup (Bcap C)=(Acup B)cap (Acup C)

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1.证明:-|||-(1) (Acup B)|C=A|(Bcup C) ;-|||-(2) (Acup B)|C=(A|C)cup (B|C) -

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    • A，B，C是任意事件，在下列各式中，不成立的是（）(A) (A-B)cup B=Acup B.-|||-(B) (Acup B)-A=B.-|||-(C) (Acup B)-AB=Aoverline

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    • 二、化简下列各式-|||-1、 (Acup B)(overline (A)cup B)(Acup overline (B))

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    • 1.已知事件A,B,C,则以下结论错误的是 () .-|||-(a) overline (AB)=overline (A)cup overline (B) (b) cup C=(Acup C)(Bcu

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    • 3.指出下列等式和命题是否成立,并说明理由:-|||-(1) cup B=(AB)cup B;-|||-(2) overline (A)B=Acup B:-|||-(3) overline (Acup

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