25 单选 (x)=x+(x-1)arcsin dfrac (x)(x+1) ,则 '(1)=-|||-

6、若 (x)=dfrac (1)(x-1), 则 f(x+1)= ()-|||-

[例26]已知 (dfrac (x+1)(x-1))=2f(x)-3x, 则 f(x)= __-|||-解:令 =dfrac (x+1)(x-1), 则 =df

将函数(x)=dfrac (1)(x+1)展开成(x-1)的幂级数2.计算(x)=dfrac (1)(x+1),其中(x)=dfrac (1)(x+1)是锥面(

1.设 (dfrac (1)(x))=x((dfrac {x)(x+1))}^2, 则 f(x)= ()-|||-(A) dfrac (1)(x)((dfrac

极限 lim _(xarrow infty )((dfrac {x+1)(x-1))}^x= () .

极限 lim _(xarrow infty )((dfrac {x+1)(x-1))}^x= __

(16) lim _(xarrow infty )((dfrac {x-1)(x+1))}^x ;

int dfrac ({x)^2+1}({(x+1))^2(x-1)}dx；；

设函数=dfrac ({x)^2}(x-1),则=dfrac ({x)^2}(x-1)=________.设函数,则=________.

[例26]已知 (dfrac (x+1)(x-1))=2f(x)-3x, 则 f(x)= __