=dfrac {1)(ln 3)(x-1)+1 D. =ln dfrac (1)(3)(x-1)

=dfrac {1)(ln 3)(x-1)+1 D. =ln dfrac (1)(3)(x-1)

lim _(xarrow 1)(dfrac (x)(x-1)-dfrac (1)(ln x))-|||-__ __

lim _(xarrow 1)(dfrac (x)(x-1)-dfrac (1)(ln x))-|||-__ __

解：lim _(xarrow 1)(dfrac (1)(x-1)-dfrac (1)(ln x))-|||-__ __解：

[题目] lim _(xarrow 1)(dfrac (x)(x-1)-dfrac (1)(ln x))

求极限 lim _(xarrow 1)(dfrac (x)(x-1)-dfrac (1)(ln x)) .

设函数 (x)=(e)^dfrac (1{x-1)}dfrac (ln |x+2|)({x)^2+x-6}求(x)=(e)^dfrac (1{x-1)}dfra

int dfrac (ln x-1)({x)^2}dx=______________________

原式为：lim _(xarrow 0)(dfrac (1)({e)^x-1}-dfrac (1)(ln (1+x)))= )=原式为：

求极限 lim _(xarrow 1)dfrac (ln [ cos (x-1)] )(1-sin dfrac {pi )(2)x}