[题目]求曲线 rho theta =1 相应于 dfrac (3)(4)leqslant theta leqslant dfrac (4)(3) 的一段弧长.

求曲线 rho theta =1 相应于 dfrac (3)(4)leqslant theta leqslant dfrac (4)(3) 的一段弧长.

6.求阿基米德螺线 rho =atheta (agt 0) 相应于 leqslant theta leqslant 2pi 的一段弧长.

6、 iint (r)^2drdtheta 其中 :acos theta leqslant rleqslant a, leqslant theta leqsl

【题目】-|||-设总体X的概率密度为-|||-(x;theta )= ,0lt xlt theta dfrac {1)(2(1-theta )),the

当theta =dfrac (pi )(4)时，theta =dfrac (pi )(4)____;当theta =dfrac (pi )(4)时，theta

当 theta =dfrac (pi )(3) 时，theta =dfrac (pi )(3)________ ，theta =dfrac (pi )(3)__

当theta =dfrac (pi )(3)时，theta =dfrac (pi )(3)______，theta =dfrac (pi )(3)______，

[题目]已知 tan theta -tan (theta +dfrac (pi )(4))=7, 则 tan theta =-|||-()-|||-

12.设曲线的极坐标方程为 rho =dfrac (1)(pi )(1-cos theta ), 求曲线在 theta =dfrac (pi )(2) 处的切线

23.计算曲线 y = ln x 上相应于 sqrt(3) leqslant x leqslant 2sqrt(2) 的一段弧的长度.23.计算曲线 $y =