设(int )_(-1)^13f(x)dx=9 , (int )_(-1)^13f(x)dx=9 , (int )_(-1)^13f(x)dx=9， 则 (int )_(-1)^13f(x)dx=9=（）。

设int_(-1)^13f(x)dx=18，int_(-1)^3f(x)dx=4，int_(-1)^3g(x)dx=3。则int_(-1)^3(1)/(5)[4

若f(x)的一个原函数是F(x)，则int f(3x-1)dx=()int f(3x-1)dx=()int f(3x-1)dx=()int f(3x-1)dx=

求-|||-(1) (int )_(-1)^1f(x)dx;-|||-(2)f(x)dx;-|||-(3) (int )_(3)^-1g(x)dx;-|||-(

(1)下列等式中正确的是-|||-()-|||-(A) int f(x)dx=f(x) (B) int df(x)=f(x)-|||-(C) dfrac (d)

设 f ( x ) 是连续奇函数且(int )_(0)^1f(x)dx=-2 则 (int )_(0)^1f(x)dx=-2设f(x)是连续奇函数且则

设(x)=dfrac (1)(1+{x)^2}+sqrt (1-{x)^2}(int )_(0)^1f(x)dx, 则 (int )_(0)^1f(x)dx=设

int f(x), dx = xe^x + C，则 int f(2x), dx = ( )A. $2xe^{2x} + C$B. $2xe^x + C$C. $

若 int f(x)dx = sin x + C，则 int xf(1-x^2)dx = ( )A. $2\sin(1-x^2)+ C$B. $-\frac{1

[例9]设f(x)在[0,1]上连续, (0)=0, (int )_(0)^1f(x)dx=0.-|||-求证:存在 xi in (0,1), 使 (int )

(13)(int )_(1)^edfrac (ln x)(x)dx;