A. $\int_{1}^{2} \frac{f(x)}{x^2} dx$
B. $\int_{2}^{1} \frac{f(x)}{x^2} dx$
C. $\int_{\frac{1}{2}}^{1} \frac{f(x)}{x^2} dx$
D. $\int_{1}^{\frac{1}{2}} \frac{f(x)}{x^2} dx$
设函数f(x)在 (-infty ,+infty ) 上连续,且 (x)=(x)^2-x(int )_(0)^1f(x)dx, 则f(x)为 (-|||-
[2023年真题]设连续函数f(x)满足： f(x+2)-f(x)=x,int_(0)^2f(x)dx=0,则 int_(1)^3f(x)dx=[2023年真题
05 设f(u)为连续函数，且int_(0)^xtf(2x-t)dt=(1)/(2)(1+x^2)，f(1)=1.则int_(1)^2f(x)dx=A. $\f
【题目】-|||-设f(x)在 (-infty ,+infty ) 内连续,则 (int )_(2)^3f(x)dx+(int )_(3)^2f(t)dt+(i
广义积分int_(1)^+infty(1)/(x^2)dx=（）A. 0B. 1C. -1D. 3
【例4】已知函数f(x)在[-1,2]上连续，且int_(-1)^0f(x)dx=2，int_(0)^1f(2x)dx=1，则int_(-1)^2f(x)dx=
设f(x)为连续函数，则(int )_(0)^1f(dfrac (x)(2))dx等于( )．(int )_(0)^1f(dfrac (x)(2))dx设f(x
B: (Xgt X)=(int )_(-infty )^xf(x)dx-|||-C: (int )_(-infty )^+infty f(x)dx=1 D: (
设 iint_(D) f(x, y), dx , dy = int_(0)^1 dx int_(x)^2x f(x, y), dy，其中 f(x, y) 是连续
2.(2020山东高数Ⅲ)已知函数f(x)在[-1,2]上连续，且int_(-1)^0f(x)dx=2,int_(0)^1f(2x)dx=1,则int_(-1)