设数列x_{n)}满足：x_(1)>0,x_(n)e^x_(n+1)=e^x_(n)-1(n=1,2,...).证明x_{n)}收敛，并求极限lim x_(n)
(45)设数列x_{n)}满足x_(1)=1,x_(n+1)=(x_(n)+2)/(x_(n)+1)(n=1,2,...),试证lim_(ntoinfty)x_
设数列|x_(n)|满足：x_(1)in(0,pi)，x_(n+1)=sin x_(n)(nin N_(+)).证明lim_(ntoinfty)x_(n)存在，
设数列x_{n)}由x_(1)in(-infty,+infty)和x_(n+1)=(1)/(3)x_(n)+(2)/(3)-(1)/(2)int_(1)^x_(
12.设x_(1),x_(2),...,x_(n),x_(n+1)是来自N(mu,sigma^2)的样本，overline(x)_(n)=(1)/(n)sum_
注：类似地，设数列x_{n)}由x_(1)in(-infty,+infty)和x_(n+1)=(1)/(3)x_(n)+(2)/(3)-(1)/(2)int_(
17.设x_(1),x_(2),...,x_(n),x_(n+1)是来自N(mu,sigma^2)的样本，又设overline(x)_(n)=(1)/(n)su
设X_(1),X_(2),...,X_(n)是来自总体X的样本，则(1)/(n-1)sum_(i=1)^n(X_(i)-overline(X))^2是（）A.
设X_(1),X_(2)...,X_(n)是来自总体X的样本，则(1)/(n-1)sum_(i=1)^n(X_(i)-overline(X))^2为(）.A.
设x_(0)=0,x_(n)=(1+2x_(n-1))/(1+x_(n-1))(n=1,2,3,...),则lim_(ntoinfty)x_(n)=设$x_{0