设数列x_{n)}由x_(1)in(-infty,+infty)和x_(n+1)=(1)/(3)x_(n)+(2)/(3)-(1)/(2)int_(1)^x_(n)e^-t^(2)dt(n=1,2,...)所确定，证明：极限lim_(ntoinfty)x_(n)存在并求此极限.

注：类似地，设数列x_{n)}由x_(1)in(-infty,+infty)和x_(n+1)=(1)/(3)x_(n)+(2)/(3)-(1)/(2)int_(

(45)设数列x_{n)}满足x_(1)=1,x_(n+1)=(x_(n)+2)/(x_(n)+1)(n=1,2,...),试证lim_(ntoinfty)x_

设数列x_{n)}满足：x_(1)>0,x_(n)e^x_(n+1)=e^x_(n)-1(n=1,2,...).证明x_{n)}收敛，并求极限lim x_(n)

(3)设X_(1)sim N(1,2),X_(2)sim N(0,3),X_(3)sim N(2,1),且X_(1),X_(2),X_(3)相互独立，则P0le

6、设X_(1)sim N(1,2)，X_(2)sim N(0,3)，X_(3)sim N(2,1)，且X_(1),X_(2),X_(3)独立，则P(0le 2

9.设x_(1)=sqrt(2),x_(n+1)=sqrt(2+x_(n))(n=1,2,...),试证数列(x_{n)}极限存在,并求此极限.9.设$x_{1

9.设x_(1)=sqrt(2),x_(n+1)=sqrt(2+x_(n))(n=1,2,...),试证数列(x_(n))极限存在,并求此极限.9.设$x_{1

9.设x_(1)=sqrt(2),x_(n+1)=sqrt(2+x_(n))(n=1,2,...),试证数列(x_{n)}极限存在,并求此极限.9.设$x_{1

(级数 第15届非数A初赛)设数列(x_{n)}满足x_(0)=(1)/(3)，x_(n+1)=(x_(n)^2)/(1-x_(n)+x_{n)^2},ngeq

37.已知x_{n)},y_{n)}满足：x_(1)=y_(1)=(1)/(2),x_(n+1)=sin x_(n),y_(n+1)=y_(n)^2(n=1,2