A. $x_{n}$是$y_{n}$的高阶无穷小.
B. $y_{n}$是$x_{n}$的高阶无穷小.
C. $x_{n}$与$y_{n}$是等价无穷小.
D. $x_{n}$与$y_{n}$是同阶但不等价的无穷小.
5、设数列x_(n),y_(n)满足lim_(n to infty)x_(n)y_(n)=0,则下列断言正确的是( )A. 若$x_{n}$发散,则$y_{n}
X_(n) 和 Y_(1) ... Y_(n) 分别取自正态总体 X sim N(mu_(1), sigma^2) 和 Y sim N(mu_(2), sigm
2.设X与Y相互独立且都服从N(0,3²)分布,X_(1),X_(2),...,X_(9),Y_(1),Y_(2),...,Y_(9)分别是来自 于X和Y的样本
(45)设数列x_{n)}满足x_(1)=1,x_(n+1)=(x_(n)+2)/(x_(n)+1)(n=1,2,...),试证lim_(ntoinfty)x_
设数列x_{n)}满足:x_(1)>0,x_(n)e^x_(n+1)=e^x_(n)-1(n=1,2,...).证明x_{n)}收敛,并求极限lim x_(n)
设数列x_{n)}由x_(1)in(-infty,+infty)和x_(n+1)=(1)/(3)x_(n)+(2)/(3)-(1)/(2)int_(1)^x_(
,X_(9) 与 Y_(1),Y_(2), ... ,Y_(9) 是分别来自动体X,Y的简单样本,统计量 W= (X_(1)+X_(2)+ ... +X_(9)
X_(9)是来自总体X的样本,Y_(1),Y_(2),... Y_(9)是来自总体Y的样本,则统计量U=(X_(1)+...+X_(9))/(sqrt(Y_(1
设(X_1, X_2, ..., X_(n_1))是来自总体X sim N(mu_1, sigma_1^2)的样本,(Y_1, Y_2, ..., Y_(n_2
注:类似地,设数列x_{n)}由x_(1)in(-infty,+infty)和x_(n+1)=(1)/(3)x_(n)+(2)/(3)-(1)/(2)int_(