已知函数F(x)=int_((pi)/(2))^x(sin t)/(t)dt,则一阶导数值F((pi)/(2))=( )A. $\frac{2}{\pi}$B.
已知 f(x) 可导且 F(x)=int_(0)^x^2 f(t) , dt,则 F(x)= ________.例2. 设 p(x)=int_(1)^sin x
267 累次积分 int_(-(pi)/(2))^(pi)/(2)dxint_(0)^sin x(x^2+ycosx)sqrt(1-y^2)dy=A. $\fr
【题目】-|||-已知 (x)=(int )_(x)^2sqrt (2+{t)^2}dt 则 f(1)= () .-|||-
【例10】已知f(x)连续,int_(0)^xtf(x-t)dt=1-cos x,求int_(0)^(pi)/(2)f(x)dx的值.【例10】已知f(x)连续
设积分上限函数f(x)=int_(0)^x^(2)cos tdt,则f(x)等于( ).A. $\cos t$B. $ 2t\cos t^{2}$C. $\co
【例4】已知函数f(x)在[-1,2]上连续,且int_(-1)^0f(x)dx=2,int_(0)^1f(2x)dx=1,则int_(-1)^2f(x)dx=
设 iint_(D) f(x, y), dx , dy = int_(0)^1 dx int_(x)^2x f(x, y), dy,其中 f(x, y) 是连续
3.设I=int_(0)^1dxint_(0)^x^(2)f(x,y)dy+int_(1)^2dxint_(0)^2-xf(x,y)dy,则交换积分次序后,I可
[例5] 设函数f(x,y)连续,则 (int )_(1)^2dx(int )_(x)^2f(x,y)dy+(int )_(1)^2dy(int )_(y)^4