计算int dfrac (1)({(1-{x)^2)}^dfrac (3{2)}}dx;计算;
int ((x)^3+1-dfrac (1)(x))dx=( ) A int ((x)^3+1-dfrac (1)(x))dx= B int ((
[题目]-|||-int (dfrac (3)(1+{x)^2}-dfrac (2)(sqrt {1-{x)^2}})dx
int dfrac (x+{x)^3}(1+{x)^4}dx
int dfrac ({x)^3}({(1+{x)^2)}^2}dx=A.int dfrac ({x)^3}({(1+{x)^2)}^2}dx=B.int df
int dfrac (1)({x)^2}sin dfrac (3)(x)dx= __
.int dfrac (sqrt {1+{x)^2}+sqrt (1-{x)^2}}(sqrt {1-{x)^4}}dx.
int dfrac (dx)(x+sqrt {1-{x)^2}}..
[题目] int dfrac (x)(sqrt {1-{x)^2}}dx
int dfrac (dx)(x+sqrt {1-{x)^2}}