5.设X1,X2,X3,X4是总体 sim N(0,1) 的简单随机样本,则 =dfrac (sqrt {3)(X)_(1)}(sqrt {{{X)_(2)}^
设(X1,X2,···,x6 )是取自正态总体N(0,σ^2)的一个样本,问:-|||-(1) dfrac ({X)_(1)+(X)_(2)+(X)_(3)+(
10.设总体 sim N(0,1), X1,X2,X3是来自X的样本,则 =dfrac (sqrt {3)X}(sqrt {{{X)_(1)}^2+({X)_(
(第一空请填写小数)设X1,X2,X3是取自正态总体N(0,4)的简单随机样本, =a(({X)_(1)}^2+({X)_(2)}^2+({X)_(3)}^2)
若X1,X2,···, _(n)(ngeqslant 2)为来自总体X1,X2,···, _(n)(ngeqslant 2)的简单随机样本,X1,X2,···,
[题目]设x1,x2,...,x5是总体 approx N(0,1) 的简单-|||-随机样本,则当 k=_ 时, =dfrac (k({x)_(1)+(x)_
设总体X服从正态分布N(2,4) ,X1,X2 10,是来自总体X的一个简单样本,则X1,X2 10 ____,X1,X2 10____,X1,X2 10___
(2)设样本X1,X2,···,X5来自总体N (0,1), =dfrac (C({X)_(1)+(X)_(2))}({({{X)_(3)}^2+({X)_(4
(2)设样本X1,X2,···,X5来自总体N (0,1), =dfrac (C({X)_(1)+(X)_(2))}({({{X)_(3)}^2+({X)_(4
7.设X1,X2,···,X6是来自总体 sim N(0,1) 的简单随机样本.-|||-(1)当 k= __ _时, =dfrac (k({X)_(1)+(X