A. $\pi+1$
B. $\pi$
C. 2
D. $\pi/2+2$
设 M=int_(-(pi)/(2))^(pi)/(2) (sin x)/(1+x^2) cos^4 x dx,N=int_(-(pi)/(2))^(pi)/(
(d)/(dx)int_(sin x)^cos x cos(pi t^2) , dt = ( ). $\frac{d}{dx}\int_{\sin x}^{\c
(15)int_(-(pi)/(2))^(pi)/(2)sqrt(cos x-cos^3)xdx;(15)$\int_{-\frac{\pi}{2}}^{\fr
(int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx=( ) .(int )_(0)^dfrac (pi {4)}dfr
【例10】已知f(x)连续,int_(0)^xtf(x-t)dt=1-cos x,求int_(0)^(pi)/(2)f(x)dx的值.【例10】已知f(x)连续
例: (int )_(0)^dfrac (pi {2)}(cos )^2dfrac (x)(2)dx= __ .
(15)(int )_(0)^pi xsqrt ({cos )^2x-(cos )^4x}dx= __
46.【2020河南】计算定积分int_(0)^(pi)/(4)(1)/(cos^2)x+3dx.46.【2020河南】计算定积分$\int_{0}^{\fra
int_(0)^asqrt(a^2)-x^(2)dx一、简答题(共10题,100.0分)6.(简答题,10.0分)$\int_{0}^{a}\sqrt{a^{2
(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}((cos )^2x+dfrac (xcos x)(1+{cos )^2x})dx