( (int )_(dfrac {pi )(4)}^dfrac (pi {3)}dfrac (x)({sin )^2x}dx ;
已知函数 (x)=dfrac (1)(2)sin (2x-dfrac (pi )(3)) x∈R,-|||-(1)求f(x)的最小正周期;-|||-(2)求f(
将函数 (x)=sin (omega x+dfrac (pi )(3))(omega gt 0) 的图象向左平移 dfrac (pi )(2) 个-|||-单位
(sin x)=dfrac (1)({cos )^2x} in (0,dfrac (pi )(2)),则(sin x)=dfrac (1)({cos )^2x}
[题目]求函数 =2sin 3x, .in [ -dfrac (pi )(6),dfrac (pi )(6)] 的反函-|||-数.
计算 lim _(xarrow dfrac {pi )(2)}dfrac (ln sin x)({(pi -2x))^2}
求lim _(xarrow dfrac {pi )(2)}dfrac (ln sin x)({(pi -2x))^2}求
2.求下列函数的极值:-|||-(6) (x)=sin x+cos x(-dfrac (pi )(2)leqslant xleqslant dfrac (pi
.函数 =ln sin x 在区间 [ dfrac (pi )(3),dfrac (2pi )(3)] 上满足罗尔定理的
7.计算下列定积分.-|||-(3) (int )_(dfrac {pi )(4)}^dfrac (pi {3)}dfrac (x)({sin )^2x}dx