3.利用定积分的几何意义,证明下列等式:-|||-(2) (int )_(0)^1sqrt (1-{x)^2}dx=dfrac (pi )(4) ;

定积分(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0

求下列定积分:-|||-(int )_(dfrac {sqrt {2)}(2)}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx

计算下列定积分.-|||-(int )_(dfrac {sqrt {2)}(2)}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx -

1.计算下列定积分:-|||-(8) (int )_(dfrac {1)(sqrt {2)}}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx

[题目]利用定积分的几何意义,求 (int )_(-3)^3sqrt (9-{x)^2}dx.

由定积分的几何意义计算积分值：int_(-2)^2sqrt(4-x^2)dx=填空题（共15题，30.0分）题型说明：共15题，每题2分。37.（2.0分）由定

求定积分 (int )_(0)^dfrac (pi {2)}sqrt (1-sin 2x)dx的值.求定积分 的值.

2.计算下列定积分:-|||-(1) (int )_(dfrac {pi )(3)}^pi sin (x+dfrac (pi )(3))dx;-|||-(2)

1.计算下列定积分:-|||-(1) (int )_(dfrac {pi )(3)}^pi sin (x+dfrac (pi )(3))dx ;-|||-(2)

.int dfrac (sqrt {1+{x)^2}+sqrt (1-{x)^2}}(sqrt {1-{x)^4}}dx.