y=0.11011; (3)x=0.10100. y= -0.10001; (4)x=13/32. y= -27/32。

32.设随机变量(X Y)具有概率密度-|||-f(x,y)= { (x+y) 0,,D(X+Y)

`t xy-|||-32.设 y=y(x) 由 ^-{a^2)du=0|=0

.已知X 和Y ,试用它们的变形补码计算出X +Y ,并指出结果是否溢出。(1)X =0.11011,Y =0.11111(2)X =0.11011,Y =-0

(x,y,z)=(x)^3+4(y)^3+4(z)^2，则(x,y,z)=(x)^3+4(y)^3+4(z)^2（）。(x,y,z)=(x)^3+4(y)^3+

x y x+y-|||-(4) y x+y x-|||-x+y x y

3.8用原码[1]不恢复余数法计算x-y(1) x=0.10101,y=0.11011。(2)x=-0.10101,y=0.11000。3.8用原码[1]不恢复

x y X+y(4)y x+y xX+y x yx y X+y(4)y x+y xX+y x y

已知 E(X)=D(X)=3 E(Y)=D(Y)=4 ,且X与Y相互独立,则-|||-D(5-Y)= __ , E(2X-3Y+4)= __ ,-|||-D(2

已知函数 =(x)^3y+3(x)^2(y)^2-x(y)^3 ,则 =(x)^3y+3(x)^2(y)^2-x(y)^3 ( ) A =(x)^3y+3

A (x,y)=(x)^3-6(x)^2y-3x(y)^2+2(y)^3 . B (x,y)=(x)^3-6(x)^2y-3x(y)^2+2(y)^3 . C