求曲线=dfrac (3{x)^2-2x+1}({x)^2+2}在点=dfrac (3{x)^2-2x+1}({x)^2+2}处的切线方程和法线方程.

(2) lim _(xarrow 1)dfrac ({x)^2-2x+1}({x)^2-1};

2.求曲线 =dfrac (1)(x) 在点 (2,dfrac (1)(2)) 处的切线方程和法-|||-线方程。

求极限：lim _(xarrow infty )((dfrac {{x)^2+2}({x)^2+2x+1})}^x求极限：

[题目]求曲线 =cos x 上点 (dfrac (pi )(3),dfrac (1)(2)) 处的切线方程-|||-和法线方程.

2.曲线 =(x)^2+dfrac (3)(x) 在点(1,4)处的切线方程为 __

11.曲线=dfrac (x)(2)+dfrac (4)(x)在点(2,3)处的切线方程为_________.11.曲线在点(2,3)处的切线方程为______

13.求曲线 =cos x 上点 (dfrac (pi )(3),dfrac (1)(2)) 处的切线方程和法线方程.

13.求曲线 =cos x 上点 (dfrac (pi )(3),dfrac (1)(2)) 处的切线方程和法线方程.

二次型 ((x)_(1),(x)_(2),(x)_(3))=2({x)_(1)}^2+2({x)_(2)}^2+2({x)_(3)}^2-2(x)_(2)(x)

例4 判断二次型-|||-((x)_(1),(x)_(2),(x)_(3))=(x)_(1)^2+2(x)_(2)^2+4(x)_(3)^2+2(x)_(1)(