A. a+b=1,a-b≠-1
B. a+b=1,a-b=-1
C. a+b≠1,a-b≠-1
D. a+b≠1,a-b=-1
设[f(x)=lim(x^2n-1+ax^2)/(x (+bx)/若X=1,X=-1均为f(x)的跳跃间断点,则[f(x)=lim(x^2n-1+ax^2)/(
(2)设 (x)=lim _(narrow infty )dfrac ({x)^2n-1+a(x)^2+bx}({x)^2n+1} 若 =1, x=-1 均为f
5.函数f(x)=lim_(ntoinfty)(1+x)/(1+x^2n),讨论函数f(x)的间断点.5.函数$f(x)=\lim_{n\to\infty}\f
9.设函数f(x)=lim_(ntoinfty)(1+x)/(1+x^2n),求f(x)的间断点并判断其类型.9.设函数$f(x)=\lim_{n\to\inf
设f(x)=underset(lim)(n→∞)(1+x)/(1+(x)^2n),求f(x)的间断点,并说明间断点所属类型.设f(x)=$\underset{l
5.设f(x+1)=lim_(ntoinfty)((n+x)/(n-2))^n,则f(x)=( )A. $e^{x-1}$B. $e^{x+2}$C. $e^
【例1.25】讨论函数f(x)=lim_(ntoinfty)(1-x^2n)/(1+x^2n)x的连续性,若有间断点,判断其类型.【例1.25】讨论函数$f(x
设函数 f(x)= lim_(n to infty) (1 + x)/(1 + x^2n),则下列结论成立的是()A. $f(x)$ 无间断点B. $f(x)$
设(x)=lim _(narrow infty )dfrac ({x)^2n-1+a(x)^2+bx}({x)^2n+1}-|||-+bx/,若(x)=lim
[题目]设 (x)=lim _(narrow infty )dfrac ((n-1)x)(n{x)^2+1} 则f(x)的间断点为 x=-|||-__ ..