(2)设 (x)=lim _(narrow infty )dfrac ({x)^2n-1+a(x)^2+bx}({x)^2n+1} 若 =1, x=-1 均为f(x)的跳跃间断点,则 () ()-|||-(A) +b=1, -bneq -1 (B) +b=1, a-b=-1-|||-(C) +bneq 1, -bneq -1 (D) +bneq 1, a-b=-1

设(x)=lim _(narrow infty )dfrac ({x)^2n-1+a(x)^2+bx}({x)^2n+1}-|||-+bx/，若(x)=lim

6.设 (x)=lim _(narrow infty )dfrac ({x)^2n-1+a(x)^2+bx}({x)^2n+1} 在 (-infty ,+inf

1.设f(x)=lim_(ntoinfty)(x^2n-1+ax^2+bx)/(x^2n)+1，若x=1,x=-1均为f(x)的跳跃间断点，则（）A. a+b=

17.设函数 (x)=lim _(narrow infty )dfrac ({x)^2n-1+a(x)^2+bx}({x)^2n+1} 是连续函数,求常数a,b

设[f(x)=lim(x^2n-1+ax^2)/(x (+bx)/若X=1,X=-1均为f(x)的跳跃间断点,则[f(x)=lim(x^2n-1+ax^2)/(

[题目]设 (x)=lim _(narrow infty )dfrac ((n-1)x)(n{x)^2+1} 则f(x)的间断点为 x=-|||-__ ..

[题目]设 (x)=lim _(narrow infty )dfrac (1+x)(1+{x)^2n}, 求f(x)的间断点,并说-|||-明间断点所属类型.

设(x)=lim _(narrow infty )dfrac ({x)^n+2}(sqrt {{2)^2n+(x)^2n}}，则(x)=lim _(narrow

设 (x)=lim _(narrow infty )dfrac ({x)^n+2-(x)^-n}({x)^n+(x)^-n} 则函数(x)=lim _(narr

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