设[f(x)=lim(x^2n-1+ax^2)/(x (+bx)/若X=1,X=-1均为f(x)的跳跃间断点,则[f(x)=lim(x^2n-1+ax^2)/(x (+bx)/[f(x)=lim(x^2n-1+ax^2)/(x (+bx)/

1.设f(x)=lim_(ntoinfty)(x^2n-1+ax^2+bx)/(x^2n)+1，若x=1,x=-1均为f(x)的跳跃间断点，则（）A. a+b=

(2)设 (x)=lim _(narrow infty )dfrac ({x)^2n-1+a(x)^2+bx}({x)^2n+1} 若 =1, x=-1 均为f

[题目]设 (x)=lim _(narrow infty )dfrac ((n-1)x)(n{x)^2+1} 则f(x)的间断点为 x=-|||-__ ..

设(x)=lim _(narrow infty )dfrac ({x)^2n-1+a(x)^2+bx}({x)^2n+1}-|||-+bx/，若(x)=lim

设f（x）=underset(lim)(n→∞)(1+x)/(1+(x)^2n)，求f（x）的间断点，并说明间断点所属类型．设f（x）=$\underset{l

1.-|||-若limf(x)存在,且 (x)=(x)^3+dfrac (2{x)^2+1}(x+1)+2lim _(xarrow 1)f(x) ,则 lim

5.函数f(x)=lim_(ntoinfty)(1+x)/(1+x^2n)，讨论函数f(x)的间断点.5.函数$f(x)=\lim_{n\to\infty}\f

5.设f(x+1)=lim_(ntoinfty)((n+x)/(n-2))^n,则f(x)=（ ）A. $e^{x-1}$B. $e^{x+2}$C. $e^

若 lim_(x to 0) (f(2x))/(x) = 2，则 lim_(x to infty) xf((1)/(2x)) = ( )A. $\frac{1}

(2024·江苏)若x=1是函数f(x)=(x^3-ax)/(x^2)-x的第一类间断点，则lim_(xto0)f(x)=__.274. (2024·江苏)若x