17.设函数 (x)=lim _(narrow infty )dfrac ({x)^2n-1+a(x)^2+bx}({x)^2n+1} 是连续函数,求常数a,b.

设(x)=lim _(narrow infty )dfrac ({x)^2n-1+a(x)^2+bx}({x)^2n+1}-|||-+bx/，若(x)=lim

6.设 (x)=lim _(narrow infty )dfrac ({x)^2n-1+a(x)^2+bx}({x)^2n+1} 在 (-infty ,+inf

(2)设 (x)=lim _(narrow infty )dfrac ({x)^2n-1+a(x)^2+bx}({x)^2n+1} 若 =1, x=-1 均为f

设 (x)=lim _(narrow infty )dfrac ({x)^n+2-(x)^-n}({x)^n+(x)^-n} 则函数(x)=lim _(narr

设(x)=lim _(narrow infty )dfrac ({x)^n+2}(sqrt {{2)^2n+(x)^2n}}，则(x)=lim _(narrow

设函数(x)=lim _(narrow infty )dfrac ({x)^n+3}(sqrt {{3)^2n+(x)^2n}}(-infty lt xlt +

(2)设函数 (x)=lim _(narrow infty )sqrt [n](1+{|x|)^3n}, 则 f(x)在 (-infty ,+infty ) 内

讨论函数(x)=lim _(narrow infty )dfrac (1-{x)^2n}(1+{x)^2n}x的连续性，若有间断点，判别其类型 .讨论函数的连续

讨论函数(x)=lim _(narrow infty )dfrac (1-{x)^2n}(1+{x)^2n}x-|||-__的连续性若有间断点,判别其类型讨论函

讨论函数(x)=lim _(narrow infty )dfrac (1-{x)^2n}(1+{x)^2n}x-|||-__的连续性，若有间断点，判别其类型。讨