已知复数=dfrac (2-2i)(1+sqrt {3)i},则=dfrac (2-2i)(1+sqrt {3)i}=dfrac (2-2i)(1+sqrt {
求复数=dfrac (2i)(1-i)+dfrac (2(1-i))(i)的模与主辐角。求复数的模与主辐角。
1.9 利用复数的三角表示计算下列各式:-|||-(1) (1+i)(1-i) ;-|||-(2) (-2+3i)/(3+2i) ;-|||-(3) ((dfr
1.1.18 就以下各种情况,分别求arg z:-|||-(a) =dfrac (-2)(1+sqrt {3)i} ;-|||-(b) =dfrac (i)(-
=dfrac (arcsin x)(x)+dfrac (1)(2)ln dfrac (1-sqrt {1-{x)^2}}(1+sqrt {1-{x)^2}}
A . 0 B . =-dfrac (1-5i)(2+3i) C . =-dfrac (1-5i)(2+3i)D . =-dfrac (1-5i)(2+3i)设
) lim _(xarrow 1)dfrac ((1-sqrt {x))(1-sqrt [3](x))}({(1-x))^2}
dfrac ({mu )_(0)I}(pi R)(dfrac (1)(2)+dfrac (pi )(6))-|||-dfrac ({mu )_(0)I}(pi
复数=dfrac ((sqrt {3)+i)(2-2i)}((sqrt {3)-i)(2+2i)}的三角形式为( )=dfrac ((sqrt {3)+i)(2
1.1 计算下列各式.-|||-(1) (1+i)-(3-2i);-|||-(2) ((a-ib))^3;-|||-(3) dfrac (1)((i-1)(i-