2.3 确定下列函数的解析区域和奇点,并求出导数:-|||-(1) dfrac (1)({z)^2-1} ;-|||-(2) dfrac (az+b)(cz+d) (c,d至少有一不为零).

3.指出下列函数f(z)的解析性区域,并求出其导数:-|||-(1) ((z-1))^5 ;-|||-(2) ^3+2iz ;-|||-(3) dfrac (1

(z)=(z)^2+dfrac (1)({z)^2-1}，则其解析区域为（）(z)=(z)^2+dfrac (1)({z)^2-1}(z)=(z)^2+dfra

求下列函数的奇点:(1)dfrac (z+1)(z({z)^2+1)}; (2)dfrac (z+1)(z({z)^2+1)}求下列函数的奇点:(1)

5.7 求出下列函数在有限孤立奇点处的留数:-|||-(1) dfrac ({e)^x-1}(z);-|||-(2) dfrac ({z)^7}((z-2){(

lim _(xarrow 1)(dfrac (2)({x)^2-1}-dfrac (1)(x-1))= (-|||-A.1 B. -dfrac (1)(2) C

[ dfrac {{e)^2}({(z-1))^2},1] =-|||-A e-|||-B dfrac (1)(e)-|||-C dfrac (e)(2)-||

3.-|||-问∞是否为下列函数的孤立奇点?如果是,指出其奇点类型.-|||-(1).cos 2;-|||-(2) ((1+2z))^2;-|||-(3) df

(z)=(z)^2+dfrac (1)({z)^2+1}，则其解析区域为( )(z)=(z)^2+dfrac (1)({z)^2+1}(z)=(z)^2+dfr

当x→1时,函数dfrac ({x)^2-1}(x-1)(e)^dfrac (1{x-1)}的极限( ) (A)等于2 (B)等于0 (C)为∞ (D)不

(B) =2, =dfrac (1)(3).-|||-(C) =1, =dfrac (1)(2). (D) =1, =-dfrac (1)(3),求指导本题解题