x 4 0-|||-已知 2 -1 0 =0,则 x= __-|||-3 5 x +2

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x 4 0-|||-已知 2 -1 0 =0,则 x= __-|||-3 5 x +2

x 4 0-|||-已知 2 -1 0 =0,则 x= __-|||-3 5 x +2

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  • x -1 0 0-|||-0 x -1 0-|||-0 0 x -1 =a3x ^3+a 2x^2+a1x+a 0.-|||-a0 a1 a2 a3

    x -1 0 0-|||-0 x -1 0-|||-0 0 x -1 =a3x ^3+a 2x^2+a1x+a 0.-|||-a0 a1 a2 a3

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  • x -1 0 0-|||-0 x -1 0 =(a)_(3)(x)^3+(a)_(2)(x)^2+(a)_(1)x+(a)_(0)-|||-(5)-|||-()0 0 x -1-|||-a0 a1 a

    x -1 0 0-|||-0 x -1 0 =(a)_(3)(x)^3+(a)_(2)(x)^2+(a)_(1)x+(a)_(0)-|||-(5)-|||-()

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  • 已知函数f(x)={2,-1≤x≤0,)x+2,0<x<2,)4,x≥2,).则f(3)= ____ .

    已知函数f(x)={2,-1≤x≤0,)x+2,0<x<2,)4,x≥2,).则f(3)= ____ .已知函数f(x)=$\left\{\begin{arra

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    [题目]-|||-证明:-|||-x -1 0 0-|||-0 x -1 0 =(a)_(3)(x)^3+(a)_(2)(x)^2+(a)_(1)x+(a)_(

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  • 过点(1,1,1)、 (-2,-2,2) 和(1,-1,1) 的平面方程是 ()-|||-A x+4z+3=0-|||-B x+3z-4=0-|||-C x+4z-3=0-|||-D x+3z+4=0

    过点(1,1,1)、 (-2,-2,2) 和(1,-1,1) 的平面方程是 ()-|||-A x+4z+3=0-|||-B x+3z-4=0-|||-C x+4

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    若_(1)+((k)^2+1)(x)_(2)+2(x)_(3)=0-|||-_(1)+(2k+1)(x)_(2)+2(x)_(3)=0-|||-(x)_(1)+

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    2.试用拉普拉斯定理计算行列式-|||-1 1 1 0 0-|||-1 2 3 0 0-|||-D= 0 1 1 1 1-|||-0 x1 x2 x3 x4-|

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    1 0 0-|||-矩阵A= 1 4 2 o x 4 o 4 3 B= 0 5 0 若A与B相似,则 () .-|||-0 0 y-|||-(A) =3,

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