已知函数 z=f(x,y) 连续且满足 lim _(xarrow 1)dfrac (f(x,y)-x+2y+2)(sqrt {{(x-1))^2+(y)^2}}=0 则-|||-lim _(tarrow 0)dfrac (f(1+t,0)-f(1,2t))(t)= __

[题目]已知函数f(x,y)在点(0,0)的某个邻域内连-|||-续,且 lim _(xarrow 0)dfrac (f(x,y)-xy)({({x)^2+(y

证明:函数-|||-f(x,y)= ((x)^2+(y)^2)sin dfrac (1)(sqrt {{x)^2+(y)^2}}, ^2+(y)^2neq 0,

164 设f(x,y)有二阶连续偏导数, (x,y)=f((e)^xy,(x)^2+(y)^2), 且 f(x,y)=1-x-y+-|||-(sqrt ({(x

已知函数f(x,y)在点(0,0)的某个邻域内连续，且lim_(x to 0 cdot y to 0) (f(x,y))/(1-cos(x^2)+y^(2))=

lim _(xarrow 0),dfrac (xy)({x)^2+(y)^2}=

设函数 (x,y)=1-dfrac (cos sqrt {{x)^2+(y)^2}}(tan ({x)^2+(y)^2)} ,则当定设函数 (x,y)=1-df

3.单选题-|||-二元函数极限 lim _(xarrow 0)(dfrac (1-cos sqrt {{x)^2+(y)^2}}({e)^2+(y)^2-1}

试求下列极限(包括非正常极限):-|||-(1) lim _((x,y))(dfrac ({x)^2(y)^2}({x)^2+(y)^2}-|||-(2) li

1.试求下列极限(包括非正常极限):-|||-(1) lim _((x,y))(0,0)dfrac ({x)^2(y)^2}({x)^2+(y)^2} ;-||

lim _(xarrow 0)dfrac (sin (x{y)^2)}({y)^2}=______.=______.