[题目]已知函数f(x,y)在点(0,0)的某个邻域内连-|||-续,且 lim _(xarrow 0)dfrac (f(x,y)-xy)({({x)^2+(y)^2)}^2}=1, 则 ()-|||-A.点(0,0)不是f(x y)的极值点-|||-B.点(0,0)是f(x,y)的极大值点-|||-C.点(0,0)是f(x,y)的极小值点-|||-D.根据所给条件无法判断点(0,0)是否为f(x,y)的极-|||-值点

已知函数f(x,y)在点(0,0)的某个邻域内连续，且lim_(x to 0 cdot y to 0) (f(x,y))/(1-cos(x^2)+y^(2))=

1 已知函数f(x,y)在点(0,0)的某个邻域内连续，且 lim_((x,y)to(0,0))(f(x,y)-xy)/((x^2)+y^(2)^2)=1, 则

已知函数 z=f(x,y) 连续且满足 lim _(xarrow 1)dfrac (f(x,y)-x+2y+2)(sqrt {{(x-1))^2+(y)^2}}

函数f(x,y)= dfrac (xy)({x)^2+(y)^2},(x)^2+(y)^2neq 0-|||-0, ^2+(y)^2=0在点（0，0）处（）。

有关函数f(x,y)= dfrac (xy)(sqrt {{x)^2+(y)^2}},(x)^2+(y)^2neq 0-|||-)在点（0，0）的性态，下列说法

lim _(xarrow y)dfrac (1-xy)({x)^2+(y)^2}-|||-bigcirc (3) lim 1-√(xy+1)-|||-y)→(0

lim _(xarrow 0),dfrac (xy)({x)^2+(y)^2}=

设 f(x,y)= sin dfrac (1)({x)^2+(y)^2} , ^2+(y)^2neq 0,-|||-0, ^2+(y)^2=0,-|||-考察函

[题目]已知f(x)在 x=0 的某个邻域内连续,且-|||-(0)=0, lim _(xarrow 0)dfrac (f(x))(1-cos x)=2, 则在

8.函数f(x,y)=}(xy)/(x^2)+y^(2),x^2+y^2neq0,0,x^2+y^2=0,在(0,0)点（）A. 连续，偏导函数都存在B. 不连