则 int xf(x)dx= () .-|||-A、 dfrac (1-ln x)({x)^2}+C B、 dfrac (1)(x)+c C、 ln x-x+C
dfrac (1)(x) C. -dfrac (1)({x)^2} D. dfrac (2)({x)^3}
补考-|||- +ln |x+2|+C 则常数 int dfrac (1)(5x)dx= ()()-|||-A ln |5x|+C-|||-B 1-|||-C
下列计算错误的是 ()。A int dfrac (1)(x)dx=ln |x|+C B int dfrac (1)(x)dx=ln |x|+C C int df
(overline (X))=dfrac ({sigma )^2}(n)-|||-C. (overline (X)-mu )=dfrac ({sigma )^2
函数(x)=dfrac (ln |x|)(sqrt {1-{x)^2}}的定义域是 A(x)=dfrac (ln |x|)(sqrt {1-{x)^2}} B
定积分 ^2-dfrac (1)(x)+C ()()-|||-A dfrac (1)(2)(x)^2+dfrac (1)(x)+C-|||-B dfrac (1
1.下列函数表示不同函数的是: __-|||-(A) =|x|, =((sqrt {x))}^2-|||-(B) =ln (x)^3, =3ln x-|||-(
如果^2+(z)^2=ln dfrac (z)(x),则^2+(z)^2=ln dfrac (z)(x)( ).A.^2+(z)^2=ln dfrac (
设lim _(xarrow 0)dfrac (ln (1+x+dfrac {f(x))(x))}(x)=3,则lim _(xarrow 0)dfrac (ln