下列计算错误的是 ()。A int dfrac (1)(x)dx=ln |x|+C B int dfrac (1)(x)dx=ln |x|+C C int df
求:int dfrac (1-ln x)({(x-ln x))^2}dx求:
5.设函数 (x)=cos x, 则 (int )_(0)^dfrac (pi {2)}xf(x)dx= ()-|||-【】-|||-A.0 B 1 C -1
求不定积分int dfrac (1)(2x)sqrt (ln x)dx=().int dfrac (1)(2x)sqrt (ln x)dx=int dfrac
补考-|||- +ln |x+2|+C 则常数 int dfrac (1)(5x)dx= ()()-|||-A ln |5x|+C-|||-B 1-|||-C
(ln x)+C-|||-C. dfrac (2)(x)F(ln x)+C D. (dfrac (2)(x))+C
int dfrac (ln x-1)({x)^2}dx=______________________
int dfrac (1)(x{ln )^2x}dx
若 (x)=xf(xi ), 则 lim _(xarrow 0)dfrac ({s)^2}({x)^2}=-|||-A)1. (B) dfrac (2)(3).
[题目]若 (dfrac (1)(x))=x, 则 (x)= ()-|||-A、 dfrac (1)(x)-|||-B、 dfrac (1)({x)^2}-||