补考-|||- +ln |x+2|+C 则常数 int dfrac (1)(5x)dx= ()()-|||-A ln |5x|+C-|||-B 1-|||-C 2-|||-D 4

参考答案与解析:

相关试题

则 int xf'(x)dx= () .-|||-A、 dfrac (1-ln x)({x)^2}+C B、 dfrac (1)(x)+c C、 ln x-x+C D、 dfrac (1-2l

则 int xf(x)dx= () .-|||-A、 dfrac (1-ln x)({x)^2}+C B、 dfrac (1)(x)+c C、 ln x-x+C

  • 查看答案
  • 下列计算错误的是 ()。A int dfrac (1)(x)dx=ln |x|+C B int dfrac (1)(x)dx=ln |x|+C C int dfrac (1)(x)dx=ln |x|+

    下列计算错误的是 ()。A int dfrac (1)(x)dx=ln |x|+C B int dfrac (1)(x)dx=ln |x|+C C int df

  • 查看答案
  • (ln x)+C-|||-C. dfrac (2)(x)F(ln x)+C D. (dfrac (2)(x))+C

    (ln x)+C-|||-C. dfrac (2)(x)F(ln x)+C D. (dfrac (2)(x))+C

  • 查看答案
  • 求不定积分int dfrac (1)(2x)sqrt (ln x)dx=().int dfrac (1)(2x)sqrt (ln x)dx=int dfrac (1)(2x)sqrt (ln x)dx

    求不定积分int dfrac (1)(2x)sqrt (ln x)dx=().int dfrac (1)(2x)sqrt (ln x)dx=int dfrac

  • 查看答案
  • 函数(x)=dfrac (ln |x|)(sqrt {1-{x)^2}}的定义域是 A(x)=dfrac (ln |x|)(sqrt {1-{x)^2}} B ( -1 , 1 ) C ( -1 ,

    函数(x)=dfrac (ln |x|)(sqrt {1-{x)^2}}的定义域是 A(x)=dfrac (ln |x|)(sqrt {1-{x)^2}} B

  • 查看答案
  • 求:int dfrac (1-ln x)({(x-ln x))^2}dx

    求:int dfrac (1-ln x)({(x-ln x))^2}dx求:

  • 查看答案
  • int ((2x-5))^5dx=-|||-A dfrac (1)(8)((2x-5))^4+C-|||-B dfrac (1)(12)((2x-5))^4+C-|||-C dfrac (1)(12)

    int ((2x-5))^5dx=-|||-A dfrac (1)(8)((2x-5))^4+C-|||-B dfrac (1)(12)((2x-5))^4+C

  • 查看答案
  • 设 (int )_(0)^xuf(u)du=(e)^x-1, 则 (int )_(0)^sqrt (ln 2)(x)^3f((x)^2)dx= ()-|||-(A)1 (B) -1-|||-(C) d

    设 (int )_(0)^xuf(u)du=(e)^x-1, 则 (int )_(0)^sqrt (ln 2)(x)^3f((x)^2)dx= ()-|||-(

  • 查看答案
  • int dfrac (ln x-1)({x)^2}dx=___________

    int dfrac (ln x-1)({x)^2}dx=______________________

  • 查看答案
  • int dfrac (1)(x{ln )^2x}dx

    int dfrac (1)(x{ln )^2x}dx

  • 查看答案