9.(2025·全国一卷·高考真题)设数列(a_{n)}满足a_(1)=3,(a_(n+1))/(n)=(a_(n))/(n+1)+(1)/(n(n+1))(1)证明：(na_{n)}为等差数列；(2)设f(x)=a_(1)x+a_(2)x^2+L+a_(m)x^m，求f'(-2).

2、设级数sum_(n=1)^inftya_(n)收敛，lim_(ntoinfty)na_(n)=a.证明：sum_(n=1)^inftyn(a_(n)-a_(

(3)设a_(n)>0(n=1,2,...),S_(n)=a_(1)+a_(2)+...+a_(n),则数列S_(n)有界是数列a_(n)收敛的A. 充分必要条

设A_(1),A_(2),...,A_(n),...是事件列，若A_(n)subset A_(n+1),n=1,2,...,A=bigcap_(i=1)^inf

设数列 $\{a_n\}$ 满足 $a_1=3$，$\frac{a_{n+1}}{n}=\frac{a_n}{n+1}+\frac{1}{n(n+1)}$(1)

2025·北京·高考真题）已知a_{n)}是公差不为零的等差数列，a_(1)=-2，若a_(3),a_(4),a_(6)成等比数列，则a_(10)=（）A. -

【例14】设a_(1)+a_(2)+...+a_(n)=0，求证：方程na_(n)x^n-1+(n-1)a_(n-1)x^n-2+...+2a_(2)x+a_(

9.设a_(n)=int_(0)^1x^nsqrt(1-x^2)dx,b_(n)=int_(0)^(pi)/(2)sin^ntdt,则极限lim_(ntoinf

9.设a_(n)=int_(0)^1x^nsqrt(1-x^2)dx,b_(n)=int_(0)^(pi)/(2)sin^ntdt,则极限lim_(ntoinf

4.设A_(2n-1)=(0,(1)/(n)),A_(2n)=(0,n),n=1,2,….求出集列(A_{n)}的上限集和下限集.4.设$A_{2n-1}=\l

4.设A_(2n-1)=(0,(1)/(n)),A_(2n)=(0,n),n=1,2,···,求出集列A_(n)的上限集和下限集.4.设$A_{2n-1}=(0