化简表达式dfrac (1)(x-1)-dfrac (1)(1+x)。

原式为：lim _(xarrow 0)(dfrac (1)({e)^x-1}-dfrac (1)(ln (1+x)))= )=原式为：

化简表达式dfrac ({x)^2(y)^2-2xy}(xy)化简表达式

设(x)=dfrac (1-x)(1+x), 则(x)=dfrac (1-x)(1+x)设,则

化简表达式dfrac ({x)^3-3(x)^2+2x}({x)^2-4}化简表达式

lim _(xarrow 1)dfrac ({x)^2-1}(x-1)(e)^dfrac (1{x-1)}=

求直线dfrac (x-1)(1)=dfrac (y)(1)=dfrac (z-1)(-1)-|||-__ __在平面dfrac (x-1)(1)=dfrac

lim _(xarrow 1)(dfrac (x)(x-1)-dfrac (1)(ln x))-|||-__ __

lim _(xarrow 1)(dfrac (x)(x-1)-dfrac (1)(ln x))-|||-__ __

求函数(x)=lim _(tarrow +infty )dfrac (x+{e)^tx}(1+x{e)^tx}的分段表达式求函数的分段表达式

=dfrac {1)(ln 3)(x-1)+1 D. =ln dfrac (1)(3)(x-1)