1.设 (dfrac (1)(x))=x((dfrac {x)(x+1))}^2, 则 f(x)= ()-|||-(A) dfrac (1)(x)((dfrac
;(11) int dfrac (x+1)({x)^2+2x+5}dx ;
(x)=dfrac ({x)^2-1}((x+1)(x-2))
(5) lim _(xarrow -1)dfrac (sqrt {x+5)-2}(x+1):
int dfrac ({(x+1))^2}({x)^2}dx=
(5) lim _(xarrow infty )((dfrac {2x+3)(2x+1))}^x+1;
设(x)+(x)^2f(dfrac (1)(x))=dfrac ({x)^2+2x}(x+1) 求f(x)设
将函数(x)=dfrac (1)(x+1)展开成(x-1)的幂级数2.计算(x)=dfrac (1)(x+1),其中(x)=dfrac (1)(x+1)是锥面(
6.(2024)函数f(x) =dfrac (x+1)({x)^2+x+1}的单调增区间().dfrac (x+1)({x)^2+x+1}6.(2024)函数f
6.(2024)函数f(x) =dfrac (x+1)({x)^2+x+1}的单调增区间().dfrac (x+1)({x)^2+x+1}6.(2024)函数f