(2024·新课标I卷)已知A(0,-|||-3)和 (3,dfrac (3)(2)) 为椭圆 :dfrac ({x)^2}({a)^2}+dfrac ({y)^2}({b)^2}=1(agt -|||-gt 0) 上两点.-|||-(1)求C的离心率;-|||-(2)若过P的直线l交C于另一点B,且-|||-Delta ABP 的面积为9,求l的方程.

6.已知A(0,3)和 (3,dfrac (3)(2)) 为椭圆 :dfrac ({x)^2}({a)^2}+dfrac ({y)^2}({b)^2}=1(ag

2.(2020·新高考全国I卷)已知椭圆 :dfrac ({x)^2}({a)^2}+dfrac ({y)^2}({b)^2}=1(agt b-|||-gt 0

设L为椭圆dfrac ({x)^2}(2)+dfrac ({y)^2}(3)=1，其周长为a，则dfrac ({x)^2}(2)+dfrac ({y)^2}(3

设l为椭圆dfrac ({x)^2}(4)+dfrac ({y)^2}(3)=1，其周长记为a，则dfrac ({x)^2}(4)+dfrac ({y)^2}(

16.-|||-已知椭圆 :dfrac ({x)^2}({a)^2}+dfrac ({y)^2}({b)^2}=1(agt bgt 0) 的离心率为 dfrac

设C是椭圆 dfrac ({x)^2}(3)+dfrac ({y)^2}(2)=1, 其周长为L,设C是椭圆 dfrac ({x)^2}(3)+dfrac ({

已知_(1)=((dfrac {1)(3),-dfrac (2)(3),-dfrac (2)(3))}^T, _(2)=((-dfrac {2)(3),dfra

求椭球面dfrac ({x)^2}(2)+dfrac ({y)^2}(3)+dfrac ({z)^2}(4)=1上点dfrac ({x)^2}(2)+dfrac

(B) =-dfrac (x)(2)+dfrac (3)(2)-|||-(C) =dfrac (x)(2)+dfrac (3)(2) (D) =-dfrac (

求曲线^dfrac (2{3)}+(y)^dfrac (2{3)}=(a)^dfrac (2{3)},在点^dfrac (2{3)}+(y)^dfrac (2{