(2024·新课标I卷)已知A(0,-|||-3)和 (3,dfrac (3)(2)) 为椭圆 :dfrac ({x)^2}({a)^2}+dfrac ({y)
16.-|||-已知椭圆 :dfrac ({x)^2}({a)^2}+dfrac ({y)^2}({b)^2}=1(agt bgt 0) 的离心率为 dfrac
例3 设椭圆 :dfrac ({x)^2}({a)^2}+dfrac ({y)^2}({b)^2}=1(agt bgt 0) 的左、-|||-右焦点分别为F1,
设L为椭圆dfrac ({x)^2}(2)+dfrac ({y)^2}(3)=1,其周长为a,则dfrac ({x)^2}(2)+dfrac ({y)^2}(3
设l为椭圆dfrac ({x)^2}(4)+dfrac ({y)^2}(3)=1,其周长记为a,则dfrac ({x)^2}(4)+dfrac ({y)^2}(
设函数 (x,y)=(x)^3+(y)^3-a(x)^2-b(y)^2(agt 0,bgt 0) 有极小值 -8, 求a,b的值,使-|||-子dfrac ({
设C是椭圆 dfrac ({x)^2}(3)+dfrac ({y)^2}(2)=1, 其周长为L,设C是椭圆 dfrac ({x)^2}(3)+dfrac ({
已知_(1)=((dfrac {1)(3),-dfrac (2)(3),-dfrac (2)(3))}^T, _(2)=((-dfrac {2)(3),dfra
2.(2020·新高考全国I卷)已知椭圆 :dfrac ({x)^2}({a)^2}+dfrac ({y)^2}({b)^2}=1(agt b-|||-gt 0
3、设 (x,y)=arctan dfrac (x)(y), 则 (1,1)=-|||-(A)1; (B)0; (C) dfrac {1)(2),dfrac