在△ABC中,cosC=(2)/(3),AC=4,BC=3,则cosB=( )A. $\frac{1}{9}$B. $\frac{1}{3}$C. $\frac
[主观题]在△ABC中,∠A∶∠B∶∠C=2∶3∶4,则∠A=________,∠C=________.
4.已知 sin alpha =-dfrac (3)(5), 且α是第三象限的角,则 cos alpha = __ ,-|||-tan alpha = __ o
1)根据余弦定理AB²=AC²+BC²-2AC*BC*cosC代入得AB²=2²+1²-2x2x1x3/4=2所以AB=√22)根据余弦定理cosA=(AC²+AB²-BC²)/2AC*AB=5√2/8sinA=√14/8sin2A=2sinAcosA=2*5√2/8*√14/8=5√7/16cos2A=9/16cosC=3/4sinC=√7/4所以sin(2A+C)=sin2AcosC+cos2AsinC=5√7/16*3/4+5√2/8*√7/4=(15√7+10√14)/64在三角形ABC中,AC=
1.若角α的终边经过点 (dfrac (3)(5),-dfrac (4)(5)), 则cosα·tanα的值是 ()-|||-
(C) 3/4 (D) dfrac (1)(2)A、AB、BC、CD、DA、AB、BC、CD、D
[单选题]在△ABC中,∠C=90°,∠B=2∠A,则cos∠A=().A.B.1/2C.D.E.A、B、C、D都不正确
[单选题]在△ABC中,∠C=90°,∠B=2∠A,则cos∠A=().A.B.1/2C.D.E.A、B、C、D都不正确
(3) (int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx= () .-|||-(A) dfrac (pi )(8)+
4.设 =(tan )^3(2x), 则 = ()-|||-A.6sec^22x-|||-B.6tan^22xsec^22x-|||-C.3sin^22x co