问题描述:
解方程:2x^2+5x-3=0解方程:$$2x^2+5x-3=0$$
3(x)_(1)+2(x)_(2)-5(x)_(3)=0 .
) (x)_(1)+3(x)_(3)geqslant 3 2(x)_(2)+2(x)_(3)geqslant 5 (x)_(1),(x)_(2),(x)_(3)
解方程组: ) (x)_(1)-(x)_(2)-(x)_(3)=2 2(x)_(1)-(x)_(2)-3(x)_(3)=1 3(x)_(1)+2(x)_(2)
解下列方程:(1)x2+x=0;(2)x2-2√3x=0;(3)3x2-6x=-3;(4)4x2-121=0;(5)3x(2x+1)=4x+2;(6)(x-4)
求齐次线性方程组-|||- ) 2(x)_(1)+(x)_(2)-(x)_(3)+(x)_(4)-3(x)_(5)=0 (x)_(1)+(x)_(2)-(x)
x 4 0-|||-已知 2 -1 0 =0,则 x= __-|||-3 5 x +2
x 4 0-|||-已知 2 -1 0 =0,则 x= __-|||-3 5 x +2
(int )_(0)^5dfrac (2{x)^2+3x-5}(x+3)dx
5.线性方程组 ) (x)_(1)-(x)_(2)=(a)_(1) 2(x)_(2)-(x)_(3)=(a)_(2) (x)_(1)+(x)_(2)-(x)