
[题目] Delta ABC 中-|||-angle B=angle A+(10)^circ angle C=angle B+(10)^circ 求 Del
如图,在 Delta ABC 中, angle BAE=angle CAE ,-|||-angle ADC=(90)^circ angle B=(40)^ci
2.已知:如图,在 Delta ABC 中, angle BAE=angle CAE angle ADC=(90)^circ angle B=(40)^cir
17.-|||-如图, Delta AOD 与 Delta BOC 存在对顶角 angle AOD=angle BOC=dfrac (pi )(4) ,AC=2
cos A=dfrac (25)(31), 求 Delta ABC 的周长.
4.在 Delta ABC 中, cos C=dfrac (2)(3) =4 ,BC=3, 则 tan B= ()-|||-
(2angle(pi)/(12))^3=8angle(pi)/(4).A. 对B. 错
dfrac (2pi )(sqrt {3)} D. dfrac (pi )(6)
dfrac (2pi )(sqrt {3)}-|||-D. dfrac (pi )(6)
tan dfrac (pi )(6)= ()-|||-