已知x+y-e^xy=0，则(dy)/(dx)|_(x=0)=A 3B 1C 0D 2

(2)(e^x+y-e^x)dx+(e^x+y+e^y)dy=0;(2)$(e^{x+y}-e^{x})dx+(e^{x+y}+e^{y})dy=0;$

(6) (e^x+y-e^x)dx+(e^x+y+e^y)dy=0;(6) $(e^{x+y}-e^{x})dx+(e^{x+y}+e^{y})dy=0;$

(3)(x^2+2xy-y^2)dx+(y^2+2xy-x^2)dy=0,y|_(x=1)=1;(3)$(x^{2}+2xy-y^{2})dx+(y^{2}+2

.设方程 ^y+2xy=e 确定了函数 y=y(x), 则 dfrac (dy)(dx)(|)_(x=0)= __

(3)齐次方程 ((x)^2-xy+(y)^2)dx+x((x)^2+xy+(y)^2)dy=0 的通解是 ()-|||-(A) =(e)^arctan dfr

设函数 z = z ( x , y ) 由方程 ^2+cos (xy)+yz+x=0确定的，则 ^2+cos (xy)+yz+x=0 ( ) ( A ) dx

(2)(x^2+2xy-y^2)dx+(y^2+2xy-x^2)dy=0, y|_(x=1)=1.(2)$(x^{2}+2xy-y^{2})dx+(y^{2}+

微分方程^3dx+(2x(y)^2-1)dy=0的通解为 A ^3dx+(2x(y)^2-1)dy=0（^3dx+(2x(y)^2-1)dy=0 为任意常数）B

(B) dfrac (dy)(dx)(|)_(x=1) 不存在. (C) dfrac (dy)(dx)(|)_(x=0)=0 (D) dfrac (dy)(dx

()-|||-A (X)=0, E(Y)=2-|||-B (x)=2, E(Y)=0-|||-C (X)=3, E(Y)=1-|||-D (x)=1 E(Y)=