若Asupset B，则以下关系式AB=B，Acup B=A，overline(A)subsetoverline(B)中

三、判断以下等式是否成立1) A∪B=AB∪B; ( )2) overline(A∪BC)=overline(B∪C); ( )3) 若overline

(1)(overline(AB)cup C)(overline(AC)); (2)(Acup B)(Acupoverline(B)).6.证明:(Acup B

1.已知事件A,B,C,则以下结论错误的是 () .-|||-(a) overline (AB)=overline (A)cup overline (B) (b

5.化简:-|||-(1)(AB∪C)(AC);-|||-(2) (Acup B)(Acup overline (B)).

[题目]-|||-已知 (overline (A))=0.3, (overline (B))=0.4P(overline (AB))=0.5, 求条件概率-||

二、化简下列各式-|||-1、 (Acup B)(overline (A)cup B)(Acup overline (B))

2.设A,B为二随机事件,则 (ABcup Aoverline (B))(Acup overline (A)overline (B))= ()-|||-(A)A

2.设A,B为二随机事件,则 (ABcup Aoverline (B))(Acup overline (A)overline (B))= ()-|||-(A)A

2.设A,B是两个事件,已知 P(A)=1/4 (B)=1/2, (AB)=1/8, 求 (Acup B),-|||-P(AB),P(AB ), [ (Acup

9.设P(Acup B)=0.6，P(overline(AB))=0.4，P(B)=0.5则P(overline(Acap B))=_.9.设$P(A\cup