24 题 设 (x)=dfrac (1)(ln x)-dfrac (1)(x-1), in (0,1), 则补充定义 f(1)= ()-|||-可使f(x)在 x=1 处连续-|||-

设lim _(xarrow 0)dfrac (ln (1+x+dfrac {f(x))(x))}(x)=3，则lim _(xarrow 0)dfrac (ln

设 f(x) 在 x=1 处连续,且 dfrac (f(x)-2x)({e)^x-1-1}-dfrac (1)(ln x) 在 x=1-|||-的某去心邻域有界

8.设函数f(x)在点 x=1 处连续,且 lim _(xarrow 1)dfrac (f(x)-2)(x-1) 存在,则 f(1)= __

[例8]设f(x )在 x=1 连续,且 lim _(xarrow 1)dfrac (f(x)-2)(x-1) 存在,则 (1)= __-|||-解:因为 li

14.设 (ln x)=1+dfrac (1)(x) ,且 f(0)=0 ,则 f(x)= __

设 函数 f ( x ) 在 x = 1 处可导且lim _(xarrow 0)dfrac (f(1)-f(1-x))(2x)=1则 lim _(xarrow

[题目]-|||-设f(x)为连续函数,且 (x)=(int )_(dfrac {1)(x)}^ln xf(t)dt, 则F(x)等于 ()-|||-(A) d

1.设 (x)=dfrac (1)(1-{x)^2}, 求 (-x),f[ f(x)] ,f[ dfrac (1)(f(x))]

设 lim _(xarrow 0)((1+x+dfrac {f(x))(x))}^dfrac (1{x)}=(e)^3 ,则 lim _(xarrow 0)((

1.设 (dfrac (1)(x))=x((dfrac {x)(x+1))}^2, 则 f(x)= ()-|||-(A) dfrac (1)(x)((dfrac