0,\\&{{\lim}} _{x \rightarrow \infty}\{|\frac{1}{n} {{\sum}}_{i=1}^n X_i-a|<\varepsilon\}-\\&1, 则 a=（）
\end {aligned}" data-width="317" data-height="147" data-size="14041" data-format="png" style="max-width:100%">
0,\\&{{\lim}} _{x \rightarrow \infty}\{|\frac{1}{n} {{\sum}}_{i=1}^n X_i-a|<\varepsilon\}-\\&1, 则 a=（）
\end {aligned}" data-width="317" data-height="147" data-size="14041" data-format="png" style="max-width:100%">
设 f(x)=} lim_(n to infty) (x^n)/(1+x^n) & x geq 0 x & xA. $x=1$ 为跳跃间断点B. $x=0$
59 lim_(n to infty ) sum_(i=1)^n (n)/(n^2)+i^(2+1)=____59 $\lim_{n \to \infty }
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13.设 sum _(i=1)^infty (a)_(n)=1, 则 sum _(n=1)^infty ((a)_(n)-2(a)_(n+1))= __
16.-|||-□A、 (int )_(0)^1xdx=lim _(narrow infty )sum _(n=1)^infty dfrac (i)(n)cdo
令 Y = (1)/(n) sum_(i=1)^n X_i，则A. $\Cov(X_1, Y)= \frac{\sigma^2}{n}$.B. $Cov(X_1
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dfrac (1)(n-1)sum _(i=1)^n(({X)_(i)-overline (X))}^2 .-|||-n-|||-C. sqrt (dfrac
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