59 lim_(n to infty ) sum_(i=1)^n (n)/(n^2)+i^(2+1)=____

59 $\lim_{n \to \infty } \sum_{i=1}^{n} \frac{n}{n^{2}+i^{2}+1}=$____

参考答案与解析:

相关试题

极限 lim_(n to infty) (1)/(n) sum_(i=1)^n sqrt(1 + (i)/(n)) 用定积分表示为()

极限 lim_(n to infty) (1)/(n) sum_(i=1)^n sqrt(1 + (i)/(n)) 用定积分表示为()A. $\int_{0}^

  • 查看答案
  • 判别下列级数的绝对收敛性与收敛性:(1) sum_(n=1)^infty (i^n)/(n); (2) sum_(n=2)^infty (i^n)/(ln n);(3) sum_(n=0)^inft

    判别下列级数的绝对收敛性与收敛性:(1) sum_(n=1)^infty (i^n)/(n); (2) sum_(n=2)^infty (i^n)/(ln n

  • 查看答案
  • 若 lim_(n to infty) u_n = 0,则级数 sum_(n=1)^infty u_n()

    若 lim_(n to infty) u_n = 0,则级数 sum_(n=1)^infty u_n()A. 一定收敛B. 一定发散C. 绝对收敛D. 可能收敛

  • 查看答案
  • 2、设级数sum_(n=1)^inftya_(n)收敛,lim_(ntoinfty)na_(n)=a.证明:sum_(n=1)^inftyn(a_(n)-a_(n+1))=sum_(n=1)^inft

    2、设级数sum_(n=1)^inftya_(n)收敛,lim_(ntoinfty)na_(n)=a.证明:sum_(n=1)^inftyn(a_(n)-a_(

  • 查看答案
  • 13.设 sum _(i=1)^infty (a)_(n)=1, 则 sum _(n=1)^infty ((a)_(n)-2(a)_(n+1))= __

    13.设 sum _(i=1)^infty (a)_(n)=1, 则 sum _(n=1)^infty ((a)_(n)-2(a)_(n+1))= __

  • 查看答案
  • 若lim_(n to infty) b_n = +infty, 则级数sum_(n=1)^infty ((1)/(b_n) - (1)/(b_(n+1)) )的敛散性是()

    若lim_(n to infty) b_n = +infty, 则级数sum_(n=1)^infty ((1)/(b_n) - (1)/(b_(n+1)) )的

  • 查看答案
  • 根据数列极限的定义证明:(1) lim_(n to infty) (1)/(n^2) = 0;(2) lim_(n to infty) (3n+1)/(2n+1) = (3)/(2);

    根据数列极限的定义证明:(1) lim_(n to infty) (1)/(n^2) = 0;(2) lim_(n to infty) (3n+1)/(2n+1

  • 查看答案
  • 5、设级数sum_(n=1)^infty(-1)^na_(n)2^n收敛,则级数sum_(n=1)^inftya_(n)().

    5、设级数sum_(n=1)^infty(-1)^na_(n)2^n收敛,则级数sum_(n=1)^inftya_(n)().A. 条件收敛B. 绝对收敛C.

  • 查看答案
  • 12 lim_(n to infty) (1+2+3+...+(n-1))/(n^2);

    12 lim_(n to infty) (1+2+3+...+(n-1))/(n^2);12 $\lim_{n \to \infty} \frac{1+2+3+

  • 查看答案
  • 1.6 总体X-N(mu,sigma^2),x_(1),x_(2),...,x_(n)为其样本,bar(x)=(1)/(n)sum_(i=1)^nx_(i),s_(n)^2=(1)/(n)sum_(i

    1.6 总体X-N(mu,sigma^2),x_(1),x_(2),...,x_(n)为其样本,bar(x)=(1)/(n)sum_(i=1)^nx_(i),s

  • 查看答案