2.设f(z)=(e^z)/(z^2)-1,求Res(f(z),∞).2.设$f(z)=\frac{e^{z}}{z^{2}-1}$,求Res(f(z),∞).
求下列函数的奇点:(1)dfrac (z+1)(z({z)^2+1)}; (2)dfrac (z+1)(z({z)^2+1)}求下列函数的奇点:(1)
设f(z)=(sin z)/(z),则Res[f(z),0]=( )A. 0B. 1C. -1D. i
5.4已知复势为:(1) W(z)=(1+i)z ;(2) (z)=(1+i)ln (dfrac (z+1)(z-4)); (3) W(z)=-6iz+-|||
[单选题](z)=(z)^2+dfrac (1)({z)^2-1}f(z)=( )[单选题]A.B.C.D.
z=2i 为函数 f(z)=(mathrm(e)^z)/(z^2)(z^(2+4)^2) 的(A. 可去奇点B. 本性奇点C. 极点D. 解析点
4.设 (z)=dfrac (1)(z)-zsin dfrac (1)({z)^2}, 则 [ f(z),0] =-|||-(A)1; (B)2; (C)0;
z=1是函数f(z)=(tan(z-1))/(z-1)的()A. 极点;B. 本性奇点;C. 可去奇点;D. 一级零点;
设(z)=1-overline (z), _(1)=2+3i _(2)=5-i, 则 ([ f({z)_(1)-(z)_(2))-|||-__等于设等于
一、设f(z)=(1)/(2i)((z)/(overline(z))-(overline(z))/(z)),z≠0.试证:当z→0时,f(z)的极限不存在.一、